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I decided to design the transmitter side by a VCO. And I plan using LM on the receiver side. From my understanding after half-an-hour search in datasheets and sample circuits on the webdatashdet IC has two inputs; pins 2 and 3.
LMN Datasheet, PDF – Alldatasheet
The internal ‘phase comparetor’ consists of a product modulator and a low pass filter. The output of this LPF gives a voltage level which is proportional to the difference between the frequencies of these two input signals.
We can probe this voltage level from the 7th pin of LM Dtaasheet have two questions to ask: Q1 Is my explanation above correct? Does LM really work as I explained, or operate in a different manner?
LM-565 Phased Locked Loop
Is there anything necessary to correct or add? Can I leave the 4th, 8th and 9th pins not connected? The product detector creates an output signal which is proportional to the phase difference rather than to the difference of both frequencies.
Nevertheless, pull-in of the PLL occurs also when both frequencies are different. However, this is a rather complicated non-linear process. Originally Posted by LvW. Originally Posted by hkBattousai. You say that the output voltage level is proportional with the phase difference.
But how can you compare the phases of two signals if their frequencies are different? From my signal courses I remember that in order to talk about the phase difference of two signals their magnitude spectrum must be same. And, I didn’t understand what you meant by “pull-in” effect. I understand that it is dataxheet with the operation of the IC.
LMN Datasheet, PDF – Datasheet Search Engine
Can you explain it please? You form a linear control km565n with the onboard VCO and phase detector, and some off chip R’s and C’s.
In this case the VCO drives one of the phase detector inputs. As the external signal sources frequency SLOWLY moves up, for instance, the onboard VCO will sense an instantaneous phase error between its two inputs, and automatically try to correct the phase error.
As a consequence of trying to correct this error, the onboard VCO frequency also tracks higher in frequency–trying to keep the onboard VCO in phase-lock to the external source. If you monitor the tuning voltage going to the onboard VCO, you can crudely guess the external source’s frequency by simpliy measuring the tuning voltage.
Of course, if the external source frequency moves too far or too fast, the control loop will not be able to keep up. You can end up with a lag, or worst case the loop will break lock and put out meaningless information. Kind of a crude way to do things!
It looks like they use pin 1 as a single ended input, and ground pin 2, for most applications. It looks like there is NOT a frequency detector portion for the phase detector, so the lock-in range is limited. Pin 4 and 5 are connected in order to feed the detector output to the VCO input. However, if you like or if its necessary you can place a filter in between. Added after 35 minutes: Hi hkBattousai, as you were interested in the pull-in action, attached please find a pdf document showing this process as a simulation result.
I think the figure is selfexplaining. But if you have questions, send a reply. The real input reference frequency is 54 kHz instead of 55 kHz as indicated in the block diagram. Which program can simulate the LM?
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